Cheetos Combustion Assignment Data Collection peck of the Cheetos, Calorimeter and prise of the Temperature and Volume of wet supply Trial Number         ahead Mass of Cheetos [g] ± 0.01g         after(prenominal) Mass of Cheetos [g] ± 0.01g         Mass of Calorimeter [g] ± 0.01g         Volume of urine [mL] ± 0.01mL         Temperature of wet Before thaw [°C] ± 0.1°C         Temperature of Water After raise uping [°C] ± 0.1°C 1         4.74         0.12         27.90         50.00         25.0         91.0 Qualitative Observations         Cheetos are changing from orange to black in tinct as they are burned.         The flames are coming out of the group O holes.         the skinny is coming out of the oxygen holes. Data Processing and foundation variety in Temperature Tchange = Tafter - Tbefore Tchange = 91.0°C - 25.0°C Tchange = 66.0°C Change in Mass mchange = mafter - mbefore mchange = 4.74g - 0.12g mchange = 4.62g Amount of change Gained By Water -let c be the specific heat capacitor of water Heat = mwater * cwater * ?T Heat = 50.00g * 4.184j/gC° * 66.0°C Heat = 13 807.20J Amount of Heat Gained By Calorimeter -let c be the specific heat capacity for aluminum Heat = mcalorimeter * ccalorimeter * ?T Heat = 27.90g * 0.897j/gC° * 66°C Heat = 1 651.7358J Total Heat Gained Htotal = Hcalorimeter + Hwater Htotal = 13 807.20J + 1 651.7358J Htotal = 15 458.94J modulation From Joules to Kilojoules 16 458.94J = x kJ 16437.73J = 15.5kJ Amount of Heat Gained from 50g of Cheetos -let x be the mensuration of heat gained from 50g of Cheetos 16.5kJ/4.62g = x kJ/50g x = 167.7kJ Conclusion transformation From Kilocalories to Kilojoules 290kilocalories * 4.184kilojoule/kilocalorie = 1.21*103kilojoules Percentage Error Perror = [|[a ctual value - divinatory value]| / theory-! based value] * 100% Perror = [|[167.7kJ - 1.21*103kJ]|/ 1.21 * 103kJ] * 100% Perror =... If you want to get a satisfactory essay, order it on our website: BestEssayCheap.com
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